Rock Grinding
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 T05 04 20 PCS DIAMOND BURR ROCK GRINDING TOOL  US $1.50
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 T05 05 60 PCS DIAMOND BURR ROCK GRINDING TOOL US $1.50
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Calculate the horizontal distance from the base of the building to the point where the rock strikes the ground
A man stands on the roof of a building of height 16.3 m and throws a rock with a velocity of magnitude 26.1 at an angle of 25.8m/s above the horizontal. You can ignore air resistance.Calculate the magnitude of the velocity of the rock just before it strikes the ground.
I assume that the angle is 25.8 DEGREES above the horizontal.
The vertical component of the initial velocity is Vup=Sin(25.8)*26.1
The horizontal component of the initial velocity is Vh=Cos(25.8)*26.1
The time that it takes to reach the top of the arc of travel is Tup=V/g
The distance traveled up is Dup=1/2*g*Tup^2
The distance traveled down in Ddown=Dup+16.3
The time taken to travel down is Tdown=sqrt(Ddown/g*2)
The vertical component of the velocity at impact with the ground is Vdown=g*Tdown
The velocity at impact is Vi=sqrt(Vdown^2+Vh^2)
The distance traveled horizontally is Dh=(Tdown+Tup)*Vh
The distance from the base of the building is 83 meters
The velocity at impact is 33.08
